In Exercise 10.3 question 6 we have to sketch y=3|Cos(x)|-2. when we plugin 0 degrees in the input the final answer will be -2, but in absolute value graphs, the output isnt suppose o go in negative.
after u make the graph of cos(x) u make the negative values positive (we need its absolute value) and then you stretch it and move it down by two units. only the values of cos(x) cannot be 0.
In Exercise 10.3 question 6 we have to sketch y=3|Cos(x)|-2.
ReplyDeletewhen we plugin 0 degrees in the input the final answer will be -2, but in absolute value graphs, the output isnt suppose o go in negative.
after u make the graph of cos(x) u make the negative values positive (we need its absolute value) and then you stretch it and move it down by two units. only the values of cos(x) cannot be 0.
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