y = 3x - 4
Knowing the correct equation will be very helpful for part (d) i) in your Term Project Part II.
Now, before I give any hints and, surely, you will not need any hints for most of the project except for part (d) ii), I want you to post questions that you may have and that way I can post hints accordingly.
For now I will give you the following leads:
- Note that AM and MB are equal segments since M is the midpoint of AB.
- If you take any point on the perpendicular line you will see that it forms two triangles, one with points M and B and the other with points M and A. Pay attention to what kind of triangles are formed.
- Simran had suggested a great alternative idea in class for checking if lines are perpendicular or not. The method she used can also be used to prove the equidistance of any point on the perpendicular from the end points of the segment.
- Remember that you have learned about congruent figures!
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ReplyDeletein part b of the project do we need to explain the whole process of pythagorean theorem again because we've already explained it in part a.
ReplyDeletesir y = 3x - 4 we ge values of x and y that are NOT on the graph and we take their distance from a-b and try to find that WEIRDO point where the distance isnt equal(havent found that point yet) THEN wat do we do?
ReplyDeleteTo answer Sana's question, you don't need to re-explain it in part b. To answer Adeel's question, you need to now prove this to be true for ANY point which means you'll have to use some argument that can work for any point on a perpendicular through the midpoint of a line segment.
ReplyDeleteAdeel: are u asking for ques d part 1 or 2?
ReplyDeleteand sir how are we supposed to prove it to u without any specifc point if we have to claim that a line segment is being cut from its midpoint by a perpendicular line the points will have equidistant so how can we prove this argument without and example?
Well, Taha, you are asking the fundamental question. How can you prove something without referring to anything specific? Well, if you read my hints and remember what you know about right-angled triangles, you'll see that a proof can be constructed about ANY point you'll choose on the perpendicular.
ReplyDelete